Calculating Axle Maximum Load: Difference between revisions
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(Created page with "Category:Construction [http://www.chaski.org/homemachinist/viewtopic.php?f=8&t=98314#p300696 Curtis F. writes]: Let's do some math, and hopefully someone here can double...") |
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Latest revision as of 23:37, 6 February 2014
Let's do some math, and hopefully someone here can double check my numbers.
- Shaft Diameter = d = 0.500"
- Length of Shaft = l = 1.500"
- Tensile Strength, Yield of 1018 Steel = f = 53,700 psi.
The formula for determining max load:
- Formula: (d^3 x f) / (5.0912 x l)
- Therefore: (.500^3 X 53,700) / (5.0912 X 1.500) = 878.8 Lbs.
So a wheel set with 1/2" diameter journals can handle 1,757 lbs.
- A two (2) axle truck can handle 3,515 lbs.
- A two (2) truck car can handle 7,030 lbs.