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	<title>Calculating Axle Maximum Load - Revision history</title>
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	<updated>2026-04-05T16:25:17Z</updated>
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	<entry>
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		<title>Dnevil: Created page with &quot;Category:Construction  [http://www.chaski.org/homemachinist/viewtopic.php?f=8&amp;t=98314#p300696 Curtis F. writes]:  Let&#039;s do some math, and hopefully someone here can double...&quot;</title>
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		<updated>2014-02-07T04:37:35Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;&lt;a href=&quot;/mediawiki/index.php?title=Category:Construction&quot; title=&quot;Category:Construction&quot;&gt;Category:Construction&lt;/a&gt;  [http://www.chaski.org/homemachinist/viewtopic.php?f=8&amp;amp;t=98314#p300696 Curtis F. writes]:  Let&amp;#039;s do some math, and hopefully someone here can double...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;[[Category:Construction]]&lt;br /&gt;
&lt;br /&gt;
[http://www.chaski.org/homemachinist/viewtopic.php?f=8&amp;amp;t=98314#p300696 Curtis F. writes]:&lt;br /&gt;
&lt;br /&gt;
Let&amp;#039;s do some math, and hopefully someone here can double check my numbers.&lt;br /&gt;
&lt;br /&gt;
: Shaft Diameter = d = 0.500&amp;quot;&lt;br /&gt;
&lt;br /&gt;
: Length of Shaft = l = 1.500&amp;quot;&lt;br /&gt;
&lt;br /&gt;
: Tensile Strength, Yield of 1018 Steel = f = 53,700 psi.&lt;br /&gt;
&lt;br /&gt;
The formula for determining max load:&lt;br /&gt;
&lt;br /&gt;
[[File:Round Bar Stress Calcs.png|thumb|center|500px|Formulas for calculating maximum load on round solid beams. Provided by Curtis F., Chaski.org.]]&lt;br /&gt;
&lt;br /&gt;
: Formula: (d^3 x f) / (5.0912 x l)&lt;br /&gt;
&lt;br /&gt;
: Therefore: (.500^3 X 53,700) / (5.0912 X 1.500) = 878.8 Lbs.&lt;br /&gt;
&lt;br /&gt;
So a wheel set with 1/2&amp;quot; diameter journals can handle 1,757 lbs.&lt;br /&gt;
&lt;br /&gt;
: A two (2) axle truck can handle 3,515 lbs.&lt;br /&gt;
&lt;br /&gt;
: A two (2) truck car can handle 7,030 lbs.&lt;/div&gt;</summary>
		<author><name>Dnevil</name></author>
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