Calculating Axle Maximum Load

Curtis F. writes:

Let's do some math, and hopefully someone here can double check my numbers.


 * Shaft Diameter = d = 0.500"


 * Length of Shaft = l = 1.500"


 * Tensile Strength, Yield of 1018 Steel = f = 53,700 psi.

The formula for determining max load:




 * Formula: (d^3 x f) / (5.0912 x l)


 * Therefore: (.500^3 X 53,700) / (5.0912 X 1.500) = 878.8 Lbs.

So a wheel set with 1/2" diameter journals can handle 1,757 lbs.


 * A two (2) axle truck can handle 3,515 lbs.


 * A two (2) truck car can handle 7,030 lbs.